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x^2+39x-1000=0
a = 1; b = 39; c = -1000;
Δ = b2-4ac
Δ = 392-4·1·(-1000)
Δ = 5521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{5521}}{2*1}=\frac{-39-\sqrt{5521}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{5521}}{2*1}=\frac{-39+\sqrt{5521}}{2} $
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